global versus local continuity
In this entry, we establish a very basic fact about continuity:
Proposition 1.
A function between two topological spaces![]()
is continuous
![]()
iff it is continuous at every point .
Proof.
Suppose first that is continuous, and . Let be an open set in . We want to find an open set in such that . Well, let . So is open since is continuous, and . Furthermore, .
On the other hand, if is not continuous at . Then there is an open set in such that no open sets in have the property
| (1) |
Let . If is open, then has the property above, a contradiction![]()
. Since is not open, is not continuous.
∎
| Title | global versus local continuity |
|---|---|
| Canonical name | GlobalVersusLocalContinuity |
| Date of creation | 2013-03-22 19:09:07 |
| Last modified on | 2013-03-22 19:09:07 |
| Owner | CWoo (3771) |
| Last modified by | CWoo (3771) |
| Numerical id | 4 |
| Author | CWoo (3771) |
| Entry type | Result |
| Classification | msc 54C05 |
| Classification | msc 26A15 |