Maschke’s theorem
Let be a finite group![]()
, and a field of characteristic
not dividing . Then any representation of over is completely reducible.
Proof.
We need only show that any subrepresentation has a complement, and the result follows by induction![]()
.
Let be a representation of and a subrepresentation. Let be an arbitrary projection, and let
This map is obviously -equivariant, and is the identity on , and its image is contained in , since is invariant under . Thus it is an equivariant projection to , and its kernel is a complement to .
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| Title | Maschke’s theorem |
|---|---|
| Canonical name | MaschkesTheorem |
| Date of creation | 2013-03-22 13:21:16 |
| Last modified on | 2013-03-22 13:21:16 |
| Owner | bwebste (988) |
| Last modified by | bwebste (988) |
| Numerical id | 9 |
| Author | bwebste (988) |
| Entry type | Theorem |
| Classification | msc 20C15 |