Maschke’s theorem
Let be a finite group, and a field of characteristic not dividing . Then any representation of over is completely reducible.
Proof.
We need only show that any subrepresentation has a complement, and the result follows by induction.
Let be a representation of and a subrepresentation. Let be an arbitrary projection, and let
This map is obviously -equivariant, and is the identity on , and its image is contained in , since is invariant under . Thus it is an equivariant projection to , and its kernel is a complement to . ∎
Title | Maschke’s theorem |
---|---|
Canonical name | MaschkesTheorem |
Date of creation | 2013-03-22 13:21:16 |
Last modified on | 2013-03-22 13:21:16 |
Owner | bwebste (988) |
Last modified by | bwebste (988) |
Numerical id | 9 |
Author | bwebste (988) |
Entry type | Theorem |
Classification | msc 20C15 |