nonmodular sublattice
Proof.
Since is not modular, by definition it contains elements , and such that and . Then the sublattice formed by , , , and is isomorphic to . This is because while by absorption and similarly . Moreover, covers since would imply , whence and contrary to our hypothesis![]()
. By the same method, leads to a contradiction
![]()
of nonmodularity, so covers .
∎
| Title | nonmodular sublattice |
|---|---|
| Canonical name | NonmodularSublattice |
| Date of creation | 2013-03-22 16:55:25 |
| Last modified on | 2013-03-22 16:55:25 |
| Owner | ixionid (16766) |
| Last modified by | ixionid (16766) |
| Numerical id | 8 |
| Author | ixionid (16766) |
| Entry type | Theorem |
| Classification | msc 06C05 |
| Related topic | ModularLattice |