polarities and forms
Through out this article we assume . This is not a true constraint as there are only trivial dualities for .
Proposition 1.
Every duality gives rise to a non-degenerate sesquilinear form, and visa-versa.
Proof.
To see this, let be a duality. We may express this as an order preserving map . Then by the fundamental theorem of projective geometry it follows is induced by a bijective semi-linear transformation .
An semi-linear isomorphism of to is equivalent to specifying a non-degenerate sesquilinear form. In particular, define the form by (notice so ).
Now, if is a non-degenerate sesquilinear form. Then define
which is semi-linear, as is sesquilinear, and bijective, since is non-degenerate. Therefore induces an order preserving bijection , that is, a duality. ∎
We write for the image of the induced duality of a non-degenerate sesquilinear form . Notice that . (Although the form may not be reflexive, we still use the notation, but we now demonstrate that we can indeed specialize to the reflexive case.) Notice then that
Corollary 2.
Every polarity gives rise to a reflexive non-degenerate sesquilinear form, and visa-versa.
Proof.
Let be the sesquilinear form induced by the polarity . Then suppose we have such that . So . But has order 2 so . But this implies so is reflexive.
Likewise, given a reflexive non-degenerate sesquilinear form it gives rise do a duality induced by . By the reflexivity, implies also. As it follows . But by dimension arguments:
we conclude . Thus is a polarity. ∎
From the fundamental theorem of projective geometry it follows if then every order preserving map is induced by a semi-linear transformation of . In similar fashion we have
Proposition 3.
, meaning that every order reversing map can be decomposed as a where is induced from a semi-linear transformation and is a polarity.
Proof.
Let be any duality of . Then is order preserving. Thus is a projectivity so by the fundamental theorem of projective geometry is induced by a semi-linear transformation . Therefore has index 2 in . Finally it suffices to provide any polarity of to prove . For this use any reflexive non-degenerate sesquilinear form. ∎
Remark 4.
The group is the automorphism group of . In particular, the polarities account for the graph automorphisms of the Dynkin diagram of , . When there is no graph automorphism, just as there are no dualities (points are hyperplanes when .)
References
- 1 Gruenberg, K. W. and Weir, A.J. Linear Geometry 2nd Ed. (English) [B] Graduate Texts in Mathematics. 49. New York - Heidelberg - Berlin: Springer-Verlag. X, 198 p. DM 29.10; $ 12.80 (1977).
- 2 Kantor, W. M. Lectures notes on Classical Groups.
Title | polarities and forms |
Canonical name | PolaritiesAndForms |
Date of creation | 2013-03-22 15:58:13 |
Last modified on | 2013-03-22 15:58:13 |
Owner | Algeboy (12884) |
Last modified by | Algeboy (12884) |
Numerical id | 7 |
Author | Algeboy (12884) |
Entry type | Topic |
Classification | msc 51A05 |
Related topic | polarity |
Related topic | Projectivity |
Related topic | ProjectiveGeometry |
Related topic | Isometry2 |
Related topic | ProjectiveGeometry3 |
Related topic | ClassicalGroups |
Related topic | Polarity2 |
Related topic | DualityWithRespectToANonDegenerateBilinearForm |