power basis over ℤ
Let K be a number field with [K:ℚ]=n and 𝒪K denote the ring of integers of K. Then 𝒪K has a power basis over ℤ (sometimes shortened simply to power basis) if there exists α∈K such that the set {1,α,…,αn-1} is an integral basis for 𝒪K. An equivalent
(http://planetmath.org/Equivalent3) condition is that 𝒪K=ℤ[α]. Note that if such an α exists, then α∈𝒪K and K=ℚ(α).
Not all rings of integers have power bases. (See the entry biquadratic field for more details.) On the other hand, any ring of integers of a quadratic field has a power basis over ℤ, as does any ring of integers of a cyclotomic field. (See the entry examples of ring of integers of a number field for more details.)
Title | power basis over ℤ |
---|---|
Canonical name | PowerBasisOvermathbbZ |
Date of creation | 2013-03-22 15:56:55 |
Last modified on | 2013-03-22 15:56:55 |
Owner | Wkbj79 (1863) |
Last modified by | Wkbj79 (1863) |
Numerical id | 17 |
Author | Wkbj79 (1863) |
Entry type | Definition |
Classification | msc 11R04 |
Synonym | power basis |
Synonym | power bases |
Related topic | ConditionForPowerBasis |