proof of growth of exponential function
In this proof, we first restrict to when x and a are integers and only later lift this restricton.
Let a>0 be an integer, let b>1 be real, and let x be an integer.
Consider the following inequality
(1+1x)a≤1+ax(1+1x)a-1 |
If x≥2, then we have
(1+1x)a≤1+ax(32)a-1. |
Define X to be the greater of 2 and ⌈a(3/2)a-1/(1-√b)⌉; when x>X, we have
(1+1x)a≤√b. |
Rewrite xa/bx as follows when x>X:
xabx=XabXx∏n=X(1+1n)a1b |
By the inequality established above, each term in the product will be
bounded by 1/√b, hence
xabx≤XabX1(√b)x-X |
Since b>1, it is also the case that √b>1, hence we have the inequality
(√b)n≥1+n(√b-1) |
Combining the last two inequalities yields the following:
xabx≤XabX≤11+(x-X)(√b-1) |
From this, it follows that lim when and are integers.
Now we lift the restriction that be an integer. Since the power
function is increasing, , so we have for real values
of as well.
To lift the restriction on , let us write where is an integer and . Then we have
If , then . Since . Hence, for all real , we have
From this inequality, it follows that for real values of as well.
Title | proof of growth of exponential function |
---|---|
Canonical name | ProofOfGrowthOfExponentialFunction |
Date of creation | 2013-03-22 15:48:36 |
Last modified on | 2013-03-22 15:48:36 |
Owner | rspuzio (6075) |
Last modified by | rspuzio (6075) |
Numerical id | 11 |
Author | rspuzio (6075) |
Entry type | Proof |
Classification | msc 32A05 |