uniform continuity


In this entry, we extend the usual definition of a uniformly continuous function between metric spaces to arbitrary uniform spaces.

Let (X,𝒰),(Y,𝒱) be uniform spaces (the second component is the uniformity on the first component). A function f:X→Y is said to be uniformly continuous if for any V∈𝒱 there is a U∈𝒰 such that for all x∈X, U⁢[x]⊆f-1⁢(V⁢[f⁢(x)]).

Sometimes it is useful to use an alternative but equivalentMathworldPlanetmathPlanetmathPlanetmathPlanetmathPlanetmath version of uniform continuity of a function:

Proposition 1.

Suppose f:X→Y is a function and g:X×X→Y×Y is defined by g⁢(x1,x2)=(f⁢(x1),f⁢(x2)). Then f is uniformly continuous iff for any V∈V, there is a U∈U such that U⊆g-1⁢(V).

Proof.

Suppose f is uniformly continuous. Pick any V∈𝒱. Then U∈𝒰 exists with U⁢[x]⊆f-1⁢(V⁢[f⁢(x)]) for all x∈X. If (a,b)∈U, then b∈U⁢[a]⊆f-1⁢(V⁢[f⁢(a)]), or f⁢(b)⊆V⁢[f⁢(a)], or g⁢(a,b)=(f⁢(a),f⁢(b))∈V. The converseMathworldPlanetmath is straightforward. ∎

Remark. Note that we could have picked U so the inclusion becomes an equality.

Proposition 2.

. If f:X→Y is uniformly continuous, then it is continuousMathworldPlanetmathPlanetmath under the uniform topologies of X and Y.

Proof.

Let A be open in Y and set B=f-1⁢(A). Pick any x∈B. Then y=f⁢(x) has a uniform neighborhood V⁢[y]⊆A. By the uniform continuity of f, there is an entourage U∈𝒰 with x∈U⁢[x]⊆f-1⁢(V⁢[y])⊆f-1⁢(A)=B. ∎

Remark. The converse is not true, even in metric spaces.

Title uniform continuity
Canonical name UniformContinuity
Date of creation 2013-03-22 16:43:15
Last modified on 2013-03-22 16:43:15
Owner CWoo (3771)
Last modified by CWoo (3771)
Numerical id 7
Author CWoo (3771)
Entry type Definition
Classification msc 54E15
Related topic UniformlyContinuous
Related topic UniformContinuityOverLocallyCompactQuantumGroupoids
Defines uniformly continuous