uniform continuity
In this entry, we extend the usual definition of a uniformly continuous function between metric spaces to arbitrary uniform spaces.
Let (X,𝒰),(Y,𝒱) be uniform spaces (the second component is the uniformity on the first component). A function f:X→Y is said to be uniformly continuous if for any V∈𝒱 there is a U∈𝒰 such that for all x∈X, U[x]⊆f-1(V[f(x)]).
Sometimes it is useful to use an alternative but equivalent version of uniform continuity of a function:
Proposition 1.
Suppose f:X→Y is a function and g:X×X→Y×Y is defined by g(x1,x2)=(f(x1),f(x2)). Then f is uniformly continuous iff for any V∈V, there is a U∈U such that U⊆g-1(V).
Proof.
Suppose f is uniformly continuous. Pick any V∈𝒱. Then U∈𝒰 exists with U[x]⊆f-1(V[f(x)]) for all x∈X. If (a,b)∈U, then b∈U[a]⊆f-1(V[f(a)]), or f(b)⊆V[f(a)], or g(a,b)=(f(a),f(b))∈V. The converse is straightforward.
∎
Remark. Note that we could have picked U so the inclusion becomes an equality.
Proposition 2.
. If f:X→Y is uniformly continuous, then it is continuous under the uniform topologies of X and Y.
Proof.
Let A be open in Y and set B=f-1(A). Pick any x∈B. Then y=f(x) has a uniform neighborhood V[y]⊆A. By the uniform continuity of f, there is an entourage U∈𝒰 with x∈U[x]⊆f-1(V[y])⊆f-1(A)=B. ∎
Remark. The converse is not true, even in metric spaces.
Title | uniform continuity |
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Canonical name | UniformContinuity |
Date of creation | 2013-03-22 16:43:15 |
Last modified on | 2013-03-22 16:43:15 |
Owner | CWoo (3771) |
Last modified by | CWoo (3771) |
Numerical id | 7 |
Author | CWoo (3771) |
Entry type | Definition |
Classification | msc 54E15 |
Related topic | UniformlyContinuous |
Related topic | UniformContinuityOverLocallyCompactQuantumGroupoids |
Defines | uniformly continuous |