uniform continuity of Lipschitz functions


Proposition 1.

An Hölder continuous mapping is uniformly continuousPlanetmathPlanetmath. In particular any Lipschitz continuous mapping is uniformly continuous.

Proof.

Let f:XY be a mapping such that for some C>0 and α with 0<α1 one has

dY(f(p),f(q))CdX(p,q)α.

For every given ϵ>0, choose δ=(ϵ/(C+1))1α. If p,qX are given points satisfying

dX(p,q)<δ

then

dY(f(p),f(q))CδαCϵC+1<ϵ,

as desired. ∎

Title uniform continuity of Lipschitz functions
Canonical name UniformContinuityOfLipschitzFunctions
Date of creation 2013-03-22 15:06:16
Last modified on 2013-03-22 15:06:16
Owner paolini (1187)
Last modified by paolini (1187)
Numerical id 8
Author paolini (1187)
Entry type Theorem
Classification msc 26A16