exact sequences for modules with finite projective dimension
Proposition. Let be a ring and be a (left) -module, such that . If
is an exact sequence of -modules, such that each is projective, then is projective.
Proof. Since , then there exists exact sequence of -modules
Note that sequences
are projective resolutions of . Let and be maps take from these resolutions. Then generalized Schanuel’s lemma implies that and are projectively equivalent. But and . This means, that there are projective modules![]()
such that
Therefore is a direct summand of a free module![]()
(since is), which completes
the proof.
| Title | exact sequences for modules with finite projective dimension |
|---|---|
| Canonical name | ExactSequencesForModulesWithFiniteProjectiveDimension |
| Date of creation | 2013-03-22 19:04:55 |
| Last modified on | 2013-03-22 19:04:55 |
| Owner | joking (16130) |
| Last modified by | joking (16130) |
| Numerical id | 4 |
| Author | joking (16130) |
| Entry type | Corollary |
| Classification | msc 16E10 |
| Classification | msc 18G20 |
| Classification | msc 18G10 |