exact sequences for modules with finite projective dimension
Proposition. Let be a ring and be a (left) -module, such that . If
is an exact sequence of -modules, such that each is projective, then is projective.
Proof. Since , then there exists exact sequence of -modules
Note that sequences
are projective resolutions of . Let and be maps take from these resolutions. Then generalized Schanuel’s lemma implies that and are projectively equivalent. But and . This means, that there are projective modules such that
Therefore is a direct summand of a free module (since is), which completes the proof.
Title | exact sequences for modules with finite projective dimension |
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Canonical name | ExactSequencesForModulesWithFiniteProjectiveDimension |
Date of creation | 2013-03-22 19:04:55 |
Last modified on | 2013-03-22 19:04:55 |
Owner | joking (16130) |
Last modified by | joking (16130) |
Numerical id | 4 |
Author | joking (16130) |
Entry type | Corollary |
Classification | msc 16E10 |
Classification | msc 18G20 |
Classification | msc 18G10 |