continuous functions of several variables are Riemann summable


Theorem 1.
Proof.

Let D⊂ℝn be a compact subset of ℝn and let f:D→ℝ be a continuous function. Since f is defined on a compact set, f is uniformly continuousPlanetmathPlanetmath i.e. given ϵ>0 there exists δ>0 such that |x-y|≤δ⇒|f⁢(x)-f⁢(y)|≤ϵ. Let R>0 be large enough so that D⊂(-R,R)n (such an R exists because D is boundedPlanetmathPlanetmathPlanetmathPlanetmath). Let P be a polyrectangle such that D⊂∪P⊂(-R,R)n and such that every rectangle R in P has diameterPlanetmathPlanetmath which is less then δ. So one has supR⁡f⁢(x)-infR⁡f⁢(x)≤ϵ and hence

S*⁢(f,P)-S*⁢(f,P)≤ϵ⁢∑Q∈Pmeas⁢(Q)≤ϵ⁢meas⁢(P)≤ϵ⁢meas⁢[-R,R]n=ϵ⁢2n⁢Rn.

Letting ϵ→0 one concludes that S*⁢(f)=S*⁢(f). ∎

Title continuous functions of several variables are Riemann summable
Canonical name ContinuousFunctionsOfSeveralVariablesAreRiemannSummable
Date of creation 2013-03-22 15:07:56
Last modified on 2013-03-22 15:07:56
Owner paolini (1187)
Last modified by paolini (1187)
Numerical id 9
Author paolini (1187)
Entry type Theorem
Classification msc 26A42