countable algebraic sets

An algebraic set over an uncountably infinite base field $𝔽$ (like the real or complex numbers) cannot be countably infinite.

Proof: Let $S$ be a countably infinite subset of ${𝔽}^n$. By a cardinality argument (see the attachment), there must exist a line such that the projection of this set to the line is infinite. Since the projection of an algebraic set to a linear subspace is an algebraic set, the projection of $S$ to this line would be an algebraic subset of the line. However, an algebraic subset of a line is the locus of zeros of some polynomial, hence must be finite. Therefore, $S$ could not be algebraic since that would lead to a contradiction.

Title	countable algebraic sets
Canonical name	CountableAlgebraicSets
Date of creation	2013-03-22 15:44:41
Last modified on	2013-03-22 15:44:41
Owner	rspuzio (6075)
Last modified by	rspuzio (6075)
Numerical id	8
Author	rspuzio (6075)
Entry type	Theorem
Classification	msc 14A10