parameterization of equitable matrices
A n×n matrix is equitable if and only if it can be expressed in the form
mij=exp(λi-λj) |
for real numbers λ1,λ2,…,λn with λ1=0.
Assume that mij are the entries of an equitable matrix.
Since all the elements of an equitable matrix are positive by definition, we can write
mij=expμij |
with the quantities μij being real numbers (which may be positive, negative or zero).
In terms of this representation, the defining identity for an equitable matrix becomes
μik=μij+μjk |
Since this comprises a system of linear equations for the quantities μij, we could solve it using the usual methods of matrix theory. However, for this particular system of linear equations, there is a much simpler approach.
Consider the special case of the identity when i=j=k:
μii=μii+μii. |
This simplifies to
μii=0. |
In other words, all the diagonal entries are zero.
Consider the case when i=k (but does not equal j).
μij+μji=μii |
By wat we have just shown, the right hand side of this equation equals zero. Hence, we have
μij=-μji. |
In other words, the matrix of μ’s is antisymmetric.
We may express any entry in terms of the n entries μi1:
μij=μi1+μ1j=μi1-μj1 |
We will conclude by noting that if, given any n numbers λi with λ1=0, but the remaining λ’s arbitrary, we define
μij=λi-λj, |
then
μij+μjk=λi-λj+λj-λk=λi-λk=μik |
Hence, we obtain a solution of the equations
μik=μij+μjk. |
Moreover, by what we what we have seen, if we set λi=μi1, all solutions of these equations can be so described.
Q.E.D.
Title | parameterization of equitable matrices |
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Canonical name | ParameterizationOfEquitableMatrices |
Date of creation | 2013-03-22 14:58:36 |
Last modified on | 2013-03-22 14:58:36 |
Owner | rspuzio (6075) |
Last modified by | rspuzio (6075) |
Numerical id | 6 |
Author | rspuzio (6075) |
Entry type | Theorem |
Classification | msc 15-00 |