sequentially compact
A topological space X is sequentially compact if every sequence in X has a convergent subsequence.
Every sequentially compact space is countably compact. Conversely, every first countable countably compact space is sequentially compact. The ordinal space W(2ω1) is sequentially compact but not first countable, since ω1 has not countable local basis.
Next, compactness and sequential compactness are not compatible. In other words, neither one implies the other. Here’s an example of a compact space that is not sequentially compact. Let X=II, where I is the closed unit interval (with the usual topology), and X is equipped with the product topology. Then X is compact (since I is, together with Tychonoff theorem
). However, X is not sequentially compact. To see this, let fn:I→I be the function such that for any r∈I, f(r) is the n-th digit of r in its binary expansion. But the sequence f1,…,fn,… has no convergent subsequences: if fn1,…,fnk,… is a subsequence, let r∈I such that its binary expansion has its k-th digit 0 iff k is odd, and 1 otherwise. Then fn1(r),…,fnk(r),… is the sequence 0,1,0,1,…, and is clearly not convergent. The ordinal space Ω0:= is an example of a sequentially compact space that is not compact, since the cover has no finite subcover.
When is a metric space, the following are equivalent:
-
•
is sequentially compact.
- •
-
•
is compact.
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•
is totally bounded
and complete
.
Title | sequentially compact |
Canonical name | SequentiallyCompact |
Date of creation | 2013-03-22 12:50:05 |
Last modified on | 2013-03-22 12:50:05 |
Owner | mps (409) |
Last modified by | mps (409) |
Numerical id | 12 |
Author | mps (409) |
Entry type | Definition |
Classification | msc 40A05 |
Classification | msc 54D30 |
Synonym | sequential compactness |
Related topic | Compact |
Related topic | LimitPointCompact |
Related topic | BolzanoWeierstrassTheorem |
Related topic | Net |